Please answer to this question,From chapter 4 class 10th Maths {Quadratic Equations }
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11
hey there ,
=) put √(5 +√5 + ... upto infinity = x
now equation becomes ,
◆ x = √(5+x) ----------------(1)
squaring both sides , we get
=) x^2 = 5 + x
=) x^2 -x -5 = 0
=) This is the required quadratic equation
we can solve this by applying formula
=) x = -b+_√(b^2 - 4ac)/2a
_______________________________________________
Hope it will help u ^_^
=) put √(5 +√5 + ... upto infinity = x
now equation becomes ,
◆ x = √(5+x) ----------------(1)
squaring both sides , we get
=) x^2 = 5 + x
=) x^2 -x -5 = 0
=) This is the required quadratic equation
we can solve this by applying formula
=) x = -b+_√(b^2 - 4ac)/2a
_______________________________________________
Hope it will help u ^_^
Anonymous:
welcome
Answered by
3
hey there ,
=) put √(5 +√5 + ... upto infinity = x
now equation becomes ,
◆ x = √(5+x) ----------------(1)
squaring both sides , we get
=) x^2 = 5 + x
=) x^2 -x -5 = 0
=) This is the required quadratic equation
we can solve this by applying formula
=) x = -b+_√(b^2 - 4ac)/2a
_______________________________________________
Hope it will help u ^_^
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