Please answer to this question.If the diameter of a soap bubble is 10mm and it's surface tension is 0.04 N/m, find the excess pressure inside the bubble.
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Excess pressure of a soap bubble = 4T/R
Here T = 0.01N/m; D = 10mm; R = D/2 = 5mm = 0.005mm Hence excess pressure =[ 4 × 0.04] ÷ [0.005]
=0.16 ÷0.005
=32 pascals
Hope this helps..
If u liked my answer then mark it as the brainliest :p
Here T = 0.01N/m; D = 10mm; R = D/2 = 5mm = 0.005mm Hence excess pressure =[ 4 × 0.04] ÷ [0.005]
=0.16 ÷0.005
=32 pascals
Hope this helps..
If u liked my answer then mark it as the brainliest :p
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