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No. Of unit cell in ccp =4
Voids in octahedral +tetrahedral sites =2n+n
3n
Total voids =4*3=12
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Number of atoms of Au = 197/197×N(A). In N close-packed spheres there are 2N tetrahedral interstices and N octahedral interstices for a total of 3N interstices. The answer is ∴ 3N(A
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