Question

please answer to this question quickly​

Answer 1

Hey mate .....

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@@Toshika❤️❤️❤️❤️❤️

Answer 2

hey mate

given here

polynomial equation

=>3x^2 -5=0.

=>3x^2=5

=>x^2=5/3

=>x=±√(5/3)

so,

if take +ve sing

so,

x= √(5/3)

if take -ve sing

so,

x= -√(5/3)

thus:

zeros of given polynomial

= √(5/3) and - √(5/3)

relationship of zeros and coefficient

sum of zeros= -(coffi. of x )/(coffi.of x^2)

√(5/3)+ {-√5/3}= 0

√(5/3)-√(5/3)=0

0=0

and ,

product of zeros = (constant part )/coffi of x^2)

√(5/3)× [-√(5/3)]= -5/3

√(5/3) × -√(5/3) = -5/3

-5/3=-5/3

that's here all conditions is true

I hopes its helps u.✌✌

@abhi.