Math, asked by sonu6113, 1 year ago

please answer to this question quickly​

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Answered by Toshika654
0

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Answered by Anonymous
0

hey mate

given here

polynomial equation

=>3x^2 -5=0.

=>3x^2=5

=>x^2=5/3

=>x=±(5/3)

so,

if take +ve sing

so,

x= (5/3)

if take -ve sing

so,

x= -(5/3)

thus:

zeros of given polynomial

= (5/3) and - (5/3)

relationship of zeros and coefficient

sum of zeros= -(coffi. of x )/(coffi.of x^2)

(5/3)+ {-5/3}= 0

(5/3)-(5/3)=0

0=0

and ,

product of zeros = (constant part )/coffi of x^2)

(5/3)× [-(5/3)]= -5/3

(5/3) × -(5/3) = -5/3

-5/3=-5/3

that's here all conditions is true

I hopes its helps u.

@abhi.

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