Question

Please answer to this question today is my paper and I really need the answer

Answer 1

$\huge\mathfrak\red{Hey \: Mate}$

1. Acceleration at point A = 4/10

=0.4 m/s^2

✒Acceleration on point B =5/20

=0.25 m/s^2

✒Acceleration on point C = 7/30

=0.23 m/s^2

✒So, acceleration on point A is maximum

2. Total Acceleration = (4+5+7)/(10+20+30)

= 16/60

= 0.266 m/s^2

Hope it will help you ❤❤

Answer 2

$\boxed{\boxed{\huge{Answer:-}}}$

1.Maximum acceleration is more at[4,10].

as

acc =v/t

4/10=0.4m/s²

5/20= 0. 2...m/s²

7/30=0.2...m/s²

2.av velocity = total disp/total time =7/30=0.233

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