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hi mate♥️♥️♥️♥️
here is ur answer......
Number of atoms of Au = 197/197×N(A). In N close-packed spheres there are 2N tetrahedral interstices and N octahedral interstices for a total of 3N interstices. The answer is ∴ 3N(A).......hope it helps my dear
neha22222222:
thanks.. but why we take 3N..not 12 as there are 12 total void
Answered by
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in ccp arrangement effective no of atom in one unit cell is 4
so no of octahedral and tetrahedral void will be 4and 8 respectively
4atom is equivalent to 12voids therefore N no of atom is equivalent to 3N (N=avogadro no)
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