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Two dice are thrown. Find the probability of the following events:
Event A : The product of the numbers on their upper faces is 10.
Event B : The sum of the numbers on their upper faces is multiple of 9.
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Let A &B be the favorable event then
A= {(2,5),(5,2)}
n(A)=2
since n(S)=36
so,p(A)=n(A)/n(S)
=2/36
=1/18.
Similarly,
B= {(3,6),(4,5),(5,4),(6,3)}
n(B)=4
We know n(S)=36.
so,p(B)=n(B)/n(S)
=4/36
=1/9.
Hope it will help you
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