Question

please answer urgent​

Answer 1

Answer:

Given:

• A × 4 = E....(1)
• B ÷ 4 = E.....(2)
• C + 4 = E......(3)
• D - 4 = E.....(4)
• A + B + C + D = 100

To Find:

• E = ?

Solution:

• From (1)

A = E/4 ....... (5)

• From (2)

B = 4E ....... (6)

• From (3)

C = E - 4 ........(7)

• From (4)

D = E + 4 .......(8)

• Using the results (5),(6),(7) and (8)

A + B + C + D = 100

=> E/4 + 4E + (E - 4) + (E + 4) = 100

=> E/4 + 4E + E - 4 + E + 4 = 100

=> E/4 + 4E + E + E = 100

=> E/4 + 4E + 2E = 100

=> E/4 + 6E = 100

=> (E + 24E)/4 = 100

=> E + 24E = 100 × 4

=> E + 24E = 400

=> 25E = 400

=> E = 400/25

=> E = 16

$\rule{200}2$

Answer 2

Question:

• A × 4 = E
• B ÷ 4 = E
• C + 4 = E
• D - 4 = E
• A + B + C + D = 100

What is the value of E ?

Answer:

$\large\boxed{\sf{E=16}}$

Step-by-step explanation:

We have given equations,

A × 4 = E .......(i)

B ÷ 4 = E ........(ii)

C + 4 = E ........(iii)

D - 4 = E ..........(iv)

A + B + C +D = 100 ........(v)

From equation (i) and (ii), we have,

=> 4A/(B/4) = E/E

=> 16A/B = 1

=> B = 16 A .........(vi)

Adding eqn (iii) and (iv), we get,

=> C + D = 2E ........(vii)

Now, substituting the values from eqn (vi) and (vii) in eqn (v), we get,

=> A + 16A + 2E = 100 ........(viii)

But, from eqn (i), we have,

=> E = 4A

Substituting this value in eqn (viii), we get,

=> A + 16 A + 2(4A) = 100

=> 17A + 8A = 100

=> 25A = 100

=> A = 100/25

=> A = 4

Now, substituting this value in eqn (i), we get,

=> A × 4 = E

=> 4 × 4 = E

=> E = 16

Hence, the value of E = 16