Math, asked by ssameed, 11 months ago

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Answered by monasavi41198
1

Step-by-step explanation:

angles are not clear that which we have to find

follow me pleass

Answered by TRISHNADEVI
1

 \huge{ \underline{ \overline{ \mid{ \mathfrak{ \purple{ \:   \: SOLUTION \:  \: } \mid}}}}}

 \underline{ \mathfrak{ \:  \: We \:  \:  know \:  \:  that, \:  \: }} \\  \\   : \star :  \sf{ \red{Linear \:  \:  pair \:  \:  of  \:  \: angles  \:  \: must \:  \:  add \:  \:  up \:  \:  }} \\   \:  \:  \:  \:  \:  \:  \:  \: \sf{ \red{to \:  \:  180 \degree}.}

 \underline{ \text{ \: In  \: the  \: figure, \: }} \\  \\   \:  \:  \:  \:  \:  \:  \:  \: \tt{ \blue{\angle BAD + x = 180 \degree}} \\  \\  \tt {\blue {\implies 120  \degree + x = 180 \degree}} \\  \\  \tt{ \blue{ \implies x = 180 \degree  - 120  \degree }} \\  \\  \:  \:  \:  \tt{ \blue{ \therefore  \:  \:  \:  \:  \:  \:  \:  \:  \underline{ \:  \: x = 60 \degree\: }}}

 \:  \:  \:   \:  \:  \:  \:  \:   \tt{ \green{\angle ABC + y = 180 \degree}} \\  \\  \tt{ \green{ \implies 80 \degree + y = 180 \degree}} \\  \\ \tt{ \green{\implies y = 180 \degree - 80 \degree}} \\  \\  \:  \:  \:  \:  \:  \:  \:  \tt{ \green{ \therefore \: \:    \: \underline{ \:  \:  \:  y = 100 \degree \: }}}

  \: \:  \:  \:  \:  \:  \:  \:  \tt{ \pink{\angle BCD + z = 180 \degree}} \\  \\  \tt{ \pink{ \implies 60 \degree + z = 180 \degree}}  \\  \\  \tt{ \pink{\implies z = 180 \degree - 60 \degree }} \\ \\  \:  \:  \:  \:  \:  \:  \:  \:  \tt{ \pink{  \therefore \:  \:  \underline{ \:  \:  \:  z = 120 \degree \: }}}

 \mathfrak{Again,}  \\   \:  \:  \:  \:  \:  \:  \: \underline{ \mathfrak{ \:  We  \:  \: know \: \:   that, \:  }} \\  \\  :  \star :  \sf{ \red{Sum  \:  \: of  \:  \: the  \:  \: four \:  \:  angles  \:  \: of \:  \:  a \:  \:  quadrilateral \:  \:  }} \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf{ \red{is \:  \:  equal  \:  \: to \:  \:  360 \degree}.}

 \underline{ \text{ \: In  \: the \:  diagram, \: }} \\  \\   \:  \:  \:  \: \sf{ 120 \degree + 80 \degree + 60  \degree + \angle CDA = 360 \degree} \\  \\  \sf{\implies 260 \degree + \angle CDA = 360 \degree} \\  \\  \sf{ \implies \angle CDA = 360  \degree - 260 \degree } \\  \\  \:  \:  \:  \:  \:  \:  \:   \:  \: \sf{ \therefore  \:  \underline{ \: \angle CDA = 100 \degree\: }}

 \underline{ \mathfrak{ \: Now,\: }} \\  \\  \:  \:  \:  \:  \:  \:  \:  \tt{ \purple{\angle CDA + w = 180 \degree }} \\  \\  \tt{ \purple{\implies 100 \degree+ w = 180 \degree }} \\  \\  \tt{ \purple{ \implies w = 180 \degree - 100 \degree}} \\  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \tt{ \purple{  \therefore \:  \:  \underline{ \:  \:    \: w = 80 \degree\: }}}

 \bold{\therefore \:  \:  \red{ x + y + z + w }} \\  \\ \bold{ = \red{ 60 \degree + 100  \degree + 120  \degree + 80 \degree }} \\  \\  \bold{ =  \red{360 \degree }}

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