Question

please answer

using suitable identities,find the following products: (i) (3x+5)(3x+5)​

Answer 1

Answer:

9x square + 30x + 25

Step-by-step explanation:

(a+b)the whole square = a^2 + 2ab + b^2

a = 3x

b = 5

3x^2 + 2(3x)(5) + 5^2

= 9x square + 30x + 25

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Answer 2

Answer:

$\huge\mathfrak\color{E6E6FA}Answer$

Step-by-step explanation:

Given Explaination : $( 3x+5)(3x+5)$

To find : product of $(3x+5)(3x+5)$

Since The given expression is $(3x+5)(3x+5)$

It can be written as $(3x+5)(3x+5)= {(3x+5)}^{2}$

As per the identity ,${(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2}$

So, $a = 3x$

$b= 5$

${(3x + 5)}^{2} = {(3x)}^{2} + 2(3x \times 5) + {5}^{2}$

Since,${(3x + 5)}^{2} = {(3x)}^{2} + 2(3x \times 5) + {5}^{2}$

Compare squares and products

${9x}^{2} + 30x + 25$

Therefore

${(3x + 5)}^{2} = {9x}^{2} + 30x + 25$

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