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X/X+1 = X+3/X+5
X . [X+5]= [X+3] . [X+1]
X^2 + 5X = X^2 + X + 3X + 3
X^2 - X^2 = X + 3X + 3 - 5X
0 = -X + 3
X= 3
X . [X+5]= [X+3] . [X+1]
X^2 + 5X = X^2 + X + 3X + 3
X^2 - X^2 = X + 3X + 3 - 5X
0 = -X + 3
X= 3
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Answer:
AD/DB = X /X+1 is a ff
Step-by-step explanation:
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