please answer. Very important
.The angle of elevation of the top of a tower from a certain point is 30°. If the observer moves 20 meters towards the tower, the angle of elevation of the top increases by 15°. Find the height of the tower
2 points
10 (√3 + 1)
5√3
5 (√3 + 1)
10√3
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Answer:
This is the answer...
Step-by-step explanation:
Let the height of tower be (x+50) . The angle of elevation as seen by observer is 45°. So the triangle formed is 45°-45°-90° triangle and hence the observer is also at (x+50) m from the tower.
When he moves 50m closer to the tower, he is at distance x from the tower and elevation angle increased to 45°+15°=60°. The new triangle formed is 30°-60°-90° triangle with two side as (x+50) and x , i.e. the hieght of tower and new distance of observer from the tower, resptectively. Therefore -
tan(60°)=x+50x
3–√x=x+50
(3–√−1)x=50
x+50=503–√−1+50
This (x+50) is the height of tower, i.e.
503–√3–√−1
I hope this helps..!❤️
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