Question

please answer. we have to simplify. ​

Answer 1

Answer:

1

$\frac{1}{3} + \frac{4}{5} of \frac{7}{5} \div 1 \times \frac{17}{25} \\ \frac{1}{3} + \frac{28}{25} \div \frac{42}{25} \\ \frac{1}{3} + \frac{28}{25} \times \frac{25}{42} \\ \frac{1}{3} + \frac{2}{3} \\ \frac{3}{3} \\ = 1$