Question

PLEASE ANSWER WITH A PROPER EQUATION!​

Answer 1

Question:

The difference between a two-digits number and the number obtained by reversing its digits is 63. What is the difference between the digits of the number ?

Answer:

Difference between the digits is 7 .

Solution:

Let N be the original number.

Let the unit digit of the original number be y and the tens digit be x .

Then the number will be ;

N = 10x + y

Now,

Let N' be the number obtained after reversing the digits of the original number N.

Thus,

x will become the unit digit and y will become the tens digit.

Thus,

N' = 10y + x

Also,

It is given that , the difference between a two-digits number and the number obtained by reversing its digits is 63.

Thus,

=> | N - N' | = 63

=> | (10x + y) - (10y + x) | = 63

=> | 10x + y - 10y - x | = 63

=> | 9x - 9y | = 63

=> | 9•(x - y) | = 63

=> 9•| x - y | = 63

=> | x - y | = 63/9

=> | x - y | = 7

=> Difference between x and y = 7

=> Difference between the digits = 7

Hence,

The difference between the digits ia 7 .

Answer 2

Answer:

Step-by-step explanation:

Question :-

The difference between a 2 - digit number and the number obtained by interchanging its digits is 63. What is the difference between the digits of the number ?

Solution :-

Let the number at ones place is y

And the number at tens place is 10x

So the digit will be 10x + y

Interchanged digit = 10y + x

According to the Question,

⇒ 10x + y - (10y + x) = 63

⇒ 9x - 9y = 63

⇒ x - y = 7

Hence, the difference between the digits of the number is 7.