please answer with all steps ASAP...
I will surely mark brainliest to correct answer...
15 pts
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Given : Angle B < Angle A
Angle C < Angle D. ¶
To prove : AD < BC. ¶
Proof : In ∆ ABO,
Angle B < Angle A ........(Given)
AO < BO ........(As side opposite to
larger angle is longer) (I)
Now,
In ∆OCD,
Angle C < Angle D
OD < OC .......(As side opposite to
larger angle is longer) (II)
Adding (I) and (II)
AO + OD < BO + OC
AD < BC
Proved. ¶
Hope it'll help .... :-D
Angle C < Angle D. ¶
To prove : AD < BC. ¶
Proof : In ∆ ABO,
Angle B < Angle A ........(Given)
AO < BO ........(As side opposite to
larger angle is longer) (I)
Now,
In ∆OCD,
Angle C < Angle D
OD < OC .......(As side opposite to
larger angle is longer) (II)
Adding (I) and (II)
AO + OD < BO + OC
AD < BC
Proved. ¶
Hope it'll help .... :-D
anonymous64:
Dont forget that Brainliest thing.
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