Please Answer with an explanation. Find the net Resistance of the circuit. Please help.!!
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connected in series, then their net resistance can be calculated as Rseries=R1+R2 whereas when these two same resistors are connected in parallel combination then, we can calculate their net resistance as 1Rparallel=1R1+1R2. Hence, the net resistance of the given circuit diagram is Rnet=12.5Ω
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connected in series, then their net resistance can be calculated as Rseries=R1+R2 whereas when these two same resistors are connected in parallel combination then, we can calculate their net resistance as 1Rparallel=1R1+1R2. Hence, the net resistance of the given circuit diagram is Rnet=12.5Ω.
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