Question

Please Answer with an explanation. Find the net Resistance of the circuit. Please help.!!

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JEE Mains - Class-12

Answer 1

Answer:

hlo

like this

Explanation:

alculating net resistances when connected in series and when connected in parallel to each other.

Formula used:

When two resistors of resistance say R1(and)R2

connected in series, then their net resistance can be calculated as Rseries=R1+R2 whereas when these two same resistors are connected in parallel combination then, we can calculate their net resistance as 1Rparallel=1R1+1R2.

Complete step by step answer:

Let us first find the net resistance among the series combination of resistances 10Ω(and)15Ω let’s say net resistance among this series combination is R10,15 now, using series formula Rseries=R1+R2 we have,

R10,15=10+15

⇒R10,15=25Ω→(i)

Now, again we have resistances of 20Ω(and)5Ω are connected in series so using again series formula Rseries=R1+R2 , their net resistance can be written as,

R20,5=20+5

⇒R20,5=25Ω→(ii)

Now, the net resistances of R10,15(and)R20,5 both are connected in parallel combination, so using parallel combination formula 1Rparallel=1R1+1R2 we can find net resistance of circuits as:

1Rnet=1R10,15+1R20,5

Put the values from the equations R10,15=25Ω→(i) and R20,5=25Ω→(ii) we have,

1Rnet=125+125

⇒1Rnet=225

∴Rnet=12.5Ω