Math, asked by roushankrraj12, 3 months ago

please answer with explaination​

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Answered by anindyaadhikari13
10

\texttt{\textsf{\large{\underline{Solution}:}}}

We have to evaluate –

 \tt =  \sqrt[3]{\dfrac{ {3}^{3} \times  {7}^{3} \times  {5}^{9} }{ {10}^{6} }}

Cube root of a number is equal to the number raised to the power 1/3. So,

 \tt =  \dfrac{ \sqrt[3]{ {3}^{3} } \times   \sqrt[3]{{7}^{3}} \times   \sqrt[3]{{5}^{9}} }{ \sqrt[3]{{10}^{6}}}

 \tt = \dfrac{ {3}^{3 \times ^{1}/_{3}} \times  {7}^{3 \times ^{1}/_{3}}  \times  {5}^{9 \times ^{1}/_{3}}  }{ {10}^{6 \times ^{1}/_{3}} }

 \tt = \dfrac{3\times  7\times  {5}^{3}}{ {10}^{2} }

 \tt = \dfrac{21\times 125}{100}

 \tt = \dfrac{2625}{100}

 \tt =26.25

Which is our required answer.

\texttt{\textsf{\large{\underline{Answer}:}}}

  • Result = 26.25
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