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Step-by-step explanation:
Prove that n(n+1) is even using induction
The base case of n=1 gives us 2 which is even.
Assuming n=k is true,
n=(k+1) gives us k2+2k+k+2
while k(k+1)+(k+1) gives us k2+2k+1.
whats is the next step to prove this by induction? I can't seem to show
k2+2k+k+2 = k2+2k+1
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