Question

please answer with explanation only if you know​

Answer 1

Answer:

what's the question is about ?

Answer 2

Answer:

in II gram EDFG base is 14cm and height is 6cm

so,

area of ll gram EDFG =Base X Height

=14X6=> 84 cm

and area of Trap. . AGCD = 1/2 X (sum of ll sides) X h

=1/2X 33X8

= 132 cm^2

now subtract the area of ll gram EDFG by area of trap. AGCD

(132-84) cm^2

38cm^2 is the area of shaded religion AEFG

I hope this is helpful for you