Question

please answer with full explanation
 ...........................................
tan35°×tan55°=sinФ,
findФ?

Answer 1

tan35° × tan55° = sin Ф
⇒ cot(90-35)° × tan55° = sin Ф
⇒ cot55° × tan55° = sin Ф
⇒ 1/tan55° × tan55° = sin Ф
⇒ 1 = sin Ф
⇒ Ф = sin⁻¹ 1
⇒ Ф = 90°

Answer 2

tan35°×tan55°=sinø
=>cot(90°-35°)×tan55°=sinø
=>cot55°×tan55°=sinø
=>1=sinø[tanø×cotø=1]
=>sinø=sin90°
=>ø=90°