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Answer:
as FG || DE...so CAB +ABD =180 ...then X=
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Solution :-
→ ∠CBD = 46° (given)
so,
→ ∠BCA = ∠CBD (since FG || DE , Alternate interior angle.)
→ ∠BCA = 46°
now, in ∆ABC we have,
→ ∠BCA = 46°
→ BC = CA
so,
→ ∠CBA = ∠CAB = x° (Angle opposite to equal sides are equal in measure.)
then,
→ ∠BCA + ∠CBA + ∠CAB = 180° (By angle sum property.)
→ 46° + x° + x° = 180°
→ 2x° = 180° - 46°
→ 2x° = 134°
→ x° = 67° (Ans.)
Learn more :-
In ABC, AD is angle bisector,
angle BAC = 111 and AB+BD=AC find the value of angle ACB=?
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