please answer with procedure all 3 correctly to be brainliest. answers are given
1 - 103 cm²
2 - 300 cm²
3 - 256 cm²
Answers
Step-by-step explanation:
1) total area = ΔAED+ΔADC+ΔABC
= 0.5(5×10+12×6+12×7) cm²
= 0.5×206 cm²
=103 cm²
2) total area = BCDE+ABEF
= (30×5 + 0.5×(20+30)×(11-5))cm² (height of ABEF=11-5)
= (150 +150) cm²
=300 cm²
3) total area = ΔABF+ΔDCE +BFEC
= 2×ΔABF +BFEC (as, ΔABF = ΔDCE)
= (2× 0.5 ×((22-10)/2)×(8+8) + (8+8)×10) cm²
(as , CE=BF=8+8 , height of ΔABF =(22-10)/2)
=(96 +160) cm²
= 256 cm²
Step-by-step explanation:
Step-by-step explanation:
1) total area = ΔAED+ΔADC+ΔABC
= 0.5(5×10+12×6+12×7) cm²
= 0.5×206 cm²
=103 cm²
2) total area = BCDE+ABEF
= (30×5 + 0.5×(20+30)×(11-5))cm² (height of ABEF=11-5)
= (150 +150) cm²
=300 cm²
3) total area = ΔABF+ΔDCE +BFEC
= 2×ΔABF +BFEC (as, ΔABF = ΔDCE)
= (2× 0.5 ×((22-10)/2)×(8+8) + (8+8)×10) cm²
(as , CE=BF=8+8 , height of ΔABF =(22-10)/2)
=(96 +160) cm²
= 256 cm²