please answer with process
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Step-by-step explanation:
Given :-
[(2x-6)/4]-[(x-1)/8] = x/10
To find :-
Find the value of x ?
Solution :-
Given equation is [(2x-6)/4]-[(x-1)/8] = x/10
LCM of 4 and 8 = 8
=>[2(2x-6)-(x-1)]/8 = x/10
=> [(4x-12)-(x-1)]/8 = x/10
=> (4x-12-x+1)/8 = x/10
=> (3x-11)/8 = x/10
On applying cross multiplication then
=> 10(3x-11) = 8×x
=> 30x-110 = 8x
=> 30x-8x = 110
=> 22x = 110
=> x = 110/22
=>x = 5
Therefore, x = 5
Answer:-
The value of x for the given problem is 5
Check:-
If x = 5 then LHS of the given equation
[(2x-6)/4]-[(x-1)/8]
=> [2×5-6)/4] -[(5-1)/8]
=> [(10-6)/4]-(4/8)
=> (4/4)-(4/8)
=> 1-(1/2)
=> (2-1)/2
=> 1/2
and
RHS = x/10
=> 5/10
=> 1/2
LHS = RHS is true for x = 5
Verified the given relations in the given problem.
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