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LET THE SIDES OF THE TRAINGLE BE 'A', 'B', 'C' AND THE EXTENDED LINE BE 'D' .
∠DCA = 110°
∠BAC = 50°
∠DCA and ∠ABC are adjacent angles.
So, ∠DCA + ∠ABC = 180°
=> 110° + ∠ABC = 180°
=> ∠ABC = 180° - 110° = 70°
So, ∠ABC + ∠BAC + ∠x = 180° [Angle sum property]
=> 70° + 50° + x = 180°
=> 120° + x = 180°
=> x = 180° - 120° = 60°
∴ x = 60°
Hope this helps you :)
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