Math, asked by Saniyabhalla19, 9 months ago

Please answer with solution Q. 22 to Q. 30. ​

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Answered by Anonymous
3

Answer:

expansion of log120/49 is given below

Step-by-step explanation:

prime factorisation of 120= 2 ×2×2×3×5=2³ ×3×5

     Prime Factorisation of 49 = 7×7=  7²

log  120/49= log120 -log49    as loga/b= log a-log b

                     =log 2³ ×3×5  - log  7²

                       = log 2³ + log 3+ log5 - log  7²  as( log a×b= loga +log b)

                        =3log 2 +log3 + log 5 - 2log7  as( log a² = 2loga)

Answered by Anonymous
0

expansion of log120/49 is given below

Step-by-step explanation:

prime factorisation of 120= 2 ×2×2×3×5=2³ ×3×5

    Prime Factorisation of 49 = 7×7=  7²

log  120/49= log120 -log49    as loga/b= log a-log b

                    =log 2³ ×3×5  - log  7²

                      = log 2³ + log 3+ log5 - log  7²  as( log a×b= loga +log b)

                       =3log 2 +log3 + log 5 - 2log7  as( log a² = 2loga)

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