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Answer:
a)I only 1 question Answer
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Step-by-step explanation:
Prime factorising 231525, we get,
231525=3×3×3×5×5×7×7×7
=3
3
×5
2
×7
3
.
We know, a perfect cube has multiples of 3 as powers of prime factors.
Here, number of 3's is 3, number of 5's is 2 and number of 7's is 3.
So we need to multiply another 5 to the factorization to make 231525 a perfect cube.
Hence, the smallest number by which 231525 must be multiplied to obtain a perfect cube is 5.
Hence, option A is correct.
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