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p(x) = 6x³+11x²+kx-20
q(x) = 9x²-5x
Now, let p(x)+q(x) = g(x)
g(x) = (6x³+11x²+kx-20) + (9x²-5x)
= 6x³+11x²+kx-20+9x²-5x
= 6x³+11x²+9x²+kx-5x-20
= 6x³+20x²+(k-5)x-20
g(2) = 6×(2)³+20×(2)²+(k-5)×2-20
= 48+80+2(k-5)-20
= 108+2(k-5)
given, p(2) = 0 [x=2 is the root of g(x)]
108+2(k-5) = 0
2(k-5) = -108
k-5 = -108/2 = -54
k = -54+5 = -49
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