Question

please answer with steps. ​

Answer 1

Answer:

$\frac{ {( {2}^{5} )}^{2} \times {7}^{3} }{ {8}^{3} \times 7 }$

$= \frac{ {2}^{10} \times {7}^{3} }{ { ({2}^{3}) }^{3} \times 7}$

$= \frac{ {2}^{10} \times {7}^{3} }{ {2 }^{9} \times 7}$

$= {2}^{(10 - 9)} \times {7}^{(3 - 1)}$

$= {2}^{1} \times {7}^{2}$

$= 2 \times 49$

$= 98$

Step-by-step explanation:

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Answer 2

Answer:

98

Step-by-step explanation:

• $(a^{m})^{n}=a^{mn}$

• $(2^{5})^{2}=2^{10}$

• $2^{3}=8$

     $8^{3}=(2^{3} ) ^{3} =2^{9}$

• $a^{m}$ ÷ $a^{n}$ = $a^{m-n}$

       

= $\frac{2^{10} * 7^{3} }{2^{9}*7 }$

= 2 x 7²

= 98