Question

please answer with steps ​

Answer 1

Step-by-step explanation:

In ΔOAB,

∴OA=OB (radii of the same circle)

∴∠OBA=∠OAB=30

∘

(∠s opp.to equal sides of a Δ) .... (i)

Similarly, ∠OBC=∠OCB=406∘ ...(iiAdding equations (i) and (ii), we get

∠OBA+∠OBC=30

∘

+406∘

⇒∠ABC=70

∘

∵AC subtended ∠AOC at the centre and

ΔABC at any point on the circumference

∠AOC=2×∠ABC

=2×70

∘

=140