Question

please answer ..................

x^200<6^300
then greatest possible value of x
is

Answer 1

$\red{HEY\:BUDDY!!}$

HERE'S THE ANSWER...

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♠️ So , here we go

▶️ Simplifying

=> $\bold{ x^{200}\:<\:6^{300}}$

=> $\bold{ (x^{2})^{100}\:<\:(6^{3})^{100}}$

=> $\bold{ x^{2}\:<\:6^{3}}$

=> $\bold{ x^{2}\:<\:216 }$

=> $\bold{ x\:<\:\sqrt{216}}$

=> $\bold{ x\:<\:14.69}$

⏺️ So the largest possible value of x is

=> $\boxed{ x\:=14.67}$

HOPE HELPED..

$\red{JAI \:HIND..}$

:)

Answer 2

By simply their power

x^2(100)<6^3(100 )

x^2 <6^3

x^2 < 216



x<√216
x<14.69

x = 14.67 { larges possible value