Question

Please answer yes sis.number 5 and 6. Thanks.:⊂(◉‿◉)つ

Answer 1

Ans.5)

∠DAE + ∠ADE + ∠AED = 180°   [ Angle sum property of a triangle ]

  57 + ∠ADE + 90 = 180

∠ADE = 180 - 147

∠ADE = 33

∠ADE + ∠m = ∠ABC  [ Opposite angles are equal in parallelogram ]

∠m = 76 - 33

∠m = 43

Ans.6)

∠STP + ∠RPT = 180° ----(1)  [ Adjacent angles of a parallelogram ]

∵ ∠RPT = 180 - ∠RPQ   [ Angles on a straight line sum up 180° ]

Putting value in (1);

∠STP + 180 - ∠RPQ = 180

∠RPQ = ∠STP

∠RPQ = 62°

∠RPQ = ∠RQP = 62° [ Angles opposite to equal sides are equal ]

∠RPQ + ∠RQP + ∠QRP = 180°    [ Angle sum property of a triangle ]

∠QRP = 180 - 62 - 62

∠QRP = 180 - 124

∠QRP = 56°

Answer 2

Answer:

Step-by-step explanation:

5. consider triAED in which angE=90 ang A=57

sum of angles in a triangle=180

90+57+angleD=180

angD=180-147=33

consider //ABCD in which angB+angC=180

angC=180-angB

angC=180-76=104

if we take the two sides which are opposite are parallel to each other BC and AD then angD=180-angC

angC=180-104=76

m+33=76

m=76-33

m=43

6. in triPQR angP=angQ

if we consider the two lines SR and TP are parallel and TPQ is a transversal then ang T=(ang P in tri PQR)

now ang P=62

ang Q=62

now ang R=180-(62+62)=180-(124)=56