Question

Please answer yes sis.thank you so much

Answer 1

Answer:

AEB=84

EAB=48

Step-by-step explanation:

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Answer 2

Heya!

Here's ur answer..

1)

∆ ABD is an isosceles triangle..

➡ angle ABD = angle ADB = x

Therefore...

x + x + 32 = 180° ( Angle sum property of triangle)

2x = 148

x = 74

(i.e) angle ADB is 74°

Coming to ∆ BCD..

It's a equilateral triangle..

➡ All the angles of the triangle is 60°

(i.e) angle BDC = 60°

We have to find angle ADC..

angle ADC = angle ADB + angle BDC = 74° + 60°

= 134°

ANGLE ADC ➡ 134°

2)

So.. here

∆ AEB is isosceles

➡ Angle BAE = Angle ABE = 48°

By Angle sum property of triangle..

Angle BAE + Angle ABE + Angle AEB = 180°

48° + 48° + Angle AEB = 180°

Angle AEB = 84

ABCD is a cyclic quadrilateral...

➡ Angle ADE + Angle ABC = 180°

70° + 48° + angle EBC = 180°

angle EBC = 62°

Hope it helps u! ^_^