Please answer yes sis.thank you so much.answer number 3 and 4
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Step-by-step explanation:
3.
in triangle PRQ
angle P=anglePRQ=59
angle PRQ + angle SRQ= 180
(linear pair)
so angle SRQ=180-angle PRQ
= 180-59
=121
in triangle RQS
angle RQS+angleSRQ+angleRSQ=180
angle RQS=180-121-29
=20
4.in triangle EFG
angle EFG=180-90-78
=12
in triangle FHJ
angle FHJ =angle JFH
(angles opp. to equal sides are equal)
angle FHJ =(180-52)/2
=64
angle GFJ =180-12-64
=104
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