Question

please answer your question and answer the question ​

Answer 1

Answer:

Step-by-step explanation:

where AB=BC=BD=DA

A(0,0) B(S,0)

C(A+S,B) D(A,B)

AD=SQRT(a2+b2)=s

a2+b2=s2

AB=s2+02−−−−−−√=s

BC=(a+s−s)2+(b−0)2−−−−−−−−−−−−−−−−−−√=a2+b2−−−−−−√=S

CD=(a+S−a)2+(b−b)2−−−−−−−−−−−−−−−−−−√=s2−−√=S

DA=a2+b2−−−−−−√=s2−−√=S

secondly we need to prove they are perpendicular

MAC=b−0a+s−0=ba+s

MBD=b−0a−s=ba−s

MAC⋅MBD

ba+s⋅ba−s

b2a2−s2

b2−b2

-1

multipliplication of there slope is-1 so they are perpenticular

Please mark as BRAINILIEST

Answer 2

Answer:

Here is your answer buddy,

Step-by-step explanation:

Step-by-step explanation:

where AB=BC=BD=DA

A(0,0) B(S,0)

C(A+S,B) D(A,B)

AD=SQRT(a2+b2)=s

a2+b2=s2

AB=s2+02−−−−−−√=s

BC=(a+s−s)2+(b−0)2−−−−−−−−−−−−−−−−−−√=a2+b2−−−−−−√=S

CD=(a+S−a)2+(b−b)2−−−−−−−−−−−−−−−−−−√=s2−−√=S

DA=a2+b2−−−−−−√=s2−−√=S

secondly we need to prove they are perpendicular

MAC=b−0a+s−0=ba+s

MBD=b−0a−s=ba−s

MAC⋅MBD

ba+s⋅ba−s

b2a2−s2

b2−b2

-1

multiplication of there slope is-1 so they are perpendicular

Hope it helps you :)