Question

please answermy question​

Answer 1

$\left| \begin{array} {c c c} x&x+y&x+2y\\ x+2y&x&x+y\\ x+y&x+2y&x \end{array}\right|\\\\\\C_1\rightarrow C_1+C_2+C_3\\\\\\=\left| \begin{array} {c c c} 3x+3y&x+y&x+2y\\ 3x+3y&x&x+y\\3x+3y&x+2y&x \end{array}\right|\\\\\\\\=3(x+y)\left| \begin{array} {c c c} 1&x+y&x+2y\\ 1&x&x+y\\ 1&x+2y&x \end{array}\right|\\\\\\R_1\rightarrow R_1-R_2\:\:and \:\:R_3\rightarrow R_3-R_2\\\\\\\\=3(x+y)\left| \begin{array} {c c c} 0&y&y\\ 1&x&x+y\\ 0&2y&-y \end{array}\right|\\\\\\\\=3(x+y)\times\:\:-1\left|\begin{array}{c c}y&y\\ 2y&-y\end{array}\right|\\\\\\=3(x+y)\times-1(-y^2-2y^2)\\\\=3(x+y)\times -(-3y^2)\\\\=9y^2(x+y)$

Answer 2

HOPE IT HELPS☺☺......