Question

please answers by step by step explanation question no. 15 and 16

Answer 1

15. 1) sorry I can't find CD
2)x = 60 because opposite angles of rhombus are supplementary.
sum of all angles of rhombus =360
so x+y+z+angle A = 360
60+ y+ z +60= 360
120 + y +z = 360
after calculation we get y = 120 and z = 120

16. a) triangle AOB is a right angled triangle
b) In triangle AOB , using Pythagoras theorem
AB^2 =AO ^2 + OB ^2
AB^2 = 64+36
so AB ^2 =100 So AB = 10
c)As, all sides of rhombus are equal so all sides of rhombus are 10cm
Sorry for 1st question
But I hope this answers will help you.

Answer 2

Qu 15-
As we know that all the sides of a rhombus are equal then the side CD=BC= 6 cm
angle x= 60 as apposite angles in rhombus are equal.
and angle y = 180-60 = 120 (angles on same line) .
same as angle z = y = 120

Qu 16-
a)- triangle AOB is a right angled triangle as both
the diagonals of rhombus cut at 90 degree.
b)- AB^2 = AO^2 + BO^2
AB^2 = 8^2 + 6^2
AB^2 = 64 + 36

$ab = \sqrt{100}$
AB = 10 cm

c)- all the sides are equal so each side = 10 cm