Math, asked by akhil999999999, 10 months ago

please answers it instantly​

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Answers

Answered by Aayush7677
0

{[p-q] . a^[p-q-2] . [q . (aq-p)]^(-1/q) ^n - 2

Answered by Anonymous
10

Answer:

 {(p-q) × a(p-q-2) × [q(aq-p)] (-1/q)^{n-2}}

= (p-q) × (ap - aq- 2a) × (aq² - qp) (-1/q²)

= 2

Hope it will be helpful :)

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