Question

please answers the above question ​

Answer 1

Q3.1. 90°

2. 90°

3. Corresponding angles of similar triangles

Q4.

In ∆ BAC and ∆ADC,

Angle BAC = Angle ADC..............(Given)

ANGLE ACB = Angle ACD...............(Common angle)

∆ BAC ~ ∆ ADC

Therefore,

BA CA CB

---- = ---- = -----

AD CD CA

therefore,

CA^2= CB×CD

Hence, Proved

Q5.

LM×MN = LT×TN

6×10=LT×8

60= 8LT

LT = 7.5

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