Please answers the questions 5 to 11 and I will mark your answer as the brainliest
Answers
Answer:
5.Hey there!
We know that Opposite angles of a parallelogram are congruent.
Therefore, 3x-10=2x+35
=> 3x-2x = 35+10
=> x=45°
Hence, the angles are 3x-10=3*45-10=125°.
We know that adjacent angles of a parallelogram form a linear pair.
180-125=55°.
Therefore the angles of the parallelogram are 125° ,55°,125°,55°
6.
Given :- ABCD is a trapezium
AB || CD
AD = BC
To proof :-
(i)∠A = ∠B
(i) Since it's given ABCD is a trapezium
AB || CD
DA || CE ( By construction)
Therefore, ADCE is a parallelogram
So, DA = CE &
DC = AE ( Opposite side of parallelogram are equal )
But, AD = BC
Therefore, BC = CE ( Given )
∠CEB = ∠CBE ( In ∆ CBE angles opposite to equal sides are equal )
180° - ∠DAB = 180° - ∠ABC
[ ADCE is a parallelogram and ∠A + ∠E = 180° ∠B & ∠CBE form a linear pair ]
∠A = ∠B ( Cancelling 180° from both sides)
7.
Sum of two adjacent angle of rhombus is 180° and opposite angle are equal
so Q+R=180
64+R=180
R=180-64
R=116
P=R=116 degrees
S=Q=64 degress
So,PRS is a diagonal here, therefore Angle PRS =116/2=58 degrees
Step-by-step explanation:
so,here it is, I solved ur answers till 5 to 7....plz mark my answer as the brainliest as you promised