Question

please answerthe question it's important​

Answer 1

Answer:

here the simple explainable answer

Step-by-step explanation:

4. given a and b are zeroes or roots

given equation is $x^2-11x+30$ =0  ----(1)

polynomial equation of two roots is $x^2$ - (sum of the roots)$x$ + (product of the roots) = 0

sum of the roots $a+b= 11$ ----(2)

                          => $a=11-b$

produce of the roots $ab=30$ ----(3)

substitute a=11-b in equation (3)

$(11-b)b = 30 \\=> 11b-b^2 = 30\\b^2-11b+30 = 0\\(b-6)(b-5) = 0\\b=6,5$

when b=5 in equation (2)

a+5=11 => a=6

when b=6 in equation (2)

a+6=11 => a=5

then we need to find the value of $a^3+b^3$

when a=6,b=5

$a^3+b^3 = 6^3+5^3 = 216+125 = 341$

when a=5,b=6

$a^3+b^3 = 5^3+6^3 = 125+216 = 341$

therefore the answer is 341 (first option in question)

i only know 4th question but i do not know 5th question sorry :(

but i explained you 4th question clearly