Question

please answeryrj3hegg2hebv4y​

Answer 1

$\sqrt[3]{3 {}^{6} \times {4}^{3} \times {2}^{9} } \div \sqrt[3]{8 {}^{6} \times 2 {}^{6} } \\ = \sqrt[3]{3 {}^{3 \times 2} \times (2 {}^{2} ) {}^{3} \times 2 {}^{9 - 6} } \div \sqrt[3]{8 {}^{6} } \\ = \sqrt[3]{(3 {}^{2}) {}^{3} \times( 2 {}^{3}) {}^{2} \times 2 {}^{3} } \div \sqrt[3]{8 \times 8 {}^{5} } \\ = \sqrt[3]{9 {}^{3} \times 8 ^{2} \times 8 } \div \sqrt[3]{ {8}^{3} \times8 {}^{3} } \\ = 9 \times \sqrt[3]{8 {}^{3} } \div 8 \times 8 \\ = 9 \times 8 \div 64 \\ = 9 \div 8 \:$