please anwer correctly the first 2 question in above pic
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1) AB is Diameter of circle
P is any point on circumference
=> ∠APB = 90°
in Δ ΑΡΒ
∠PAB+ ∠APB + ∠PBA = 180°
∠APB = 90°
∠PAB= 40° given
∠PBA = ?
∠PBA +90° + 40° = 180°
=> ∠PBA = 50°
2) cyclic quadilatend ⇒ opposite angles are supplemetary
⇒m∠A+m∠C=180°
⇒m∠A−m∠C=20°
⇒m∠A=160°
3) l=80cm,b=40cm,h=20cm
Therefore,
TSA = 2(lb+bh+hl)=2(80×40+40×20+80×20)=11200 cm²
LSA = 2(l+b)h=2(80+40)20=4800 cm²
hope it helps you
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your answer is in above attachment
hi di, talking to you after long time
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