Question

please anwer it quickly by seeing above image​

Answer 1

See solution in image and mark as brainlist ...

Answer 2

Step-by-step explanation:

In ΔABD, we have

=> AD² = AB² - BD²

In ΔACD, we have

=>AD² = AC² - CD²

So,

=> AC² - CD²  = AB² - BD²

=> AC² = AB² + CD²  -  BD²

=>  AB² + (CD + BD)* (CD - BD)

=> AB² + BC * [(BC - BD) - BD]

=> AB² + BC * [ BC - 2 BD ]

=> AB² +BC² - 2 BC * BD

#Hope my answer will help you!