please anwer step by step .. Q. A wire has a resistence R is cut into two equal pieces.The two parts are joined in parallel .What is the resistence of the combination??
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1
Wire has resistance R.
When cut into two equal parts, resistance becomes R/2.
Parallel resistance combination = 1/Req = 1/R1 + 1/R2
R1 = R2 = R/2
1/(R/2) + 1/(R/2) = 1/Req
2/R + 2/R =1/Req
2R + 2R/R squared = 1/Req
4R/R x R = 1/Req
4/R = 1/Req
R equivalent = R/4
Resistance of combination = R/4
When cut into two equal parts, resistance becomes R/2.
Parallel resistance combination = 1/Req = 1/R1 + 1/R2
R1 = R2 = R/2
1/(R/2) + 1/(R/2) = 1/Req
2/R + 2/R =1/Req
2R + 2R/R squared = 1/Req
4R/R x R = 1/Req
4/R = 1/Req
R equivalent = R/4
Resistance of combination = R/4
palakgupta:
thnk u
Answered by
2
as given wire is cut into equal parts,
the resistances will be of both R/2, R/2.
then,
1/R'=1/R/2 +1/R/2
1/R'= 2/R + 2/R
1/R'= 2+2/R
1/R' = 4/R
R' = R/4
Required Answer.
the resistances will be of both R/2, R/2.
then,
1/R'=1/R/2 +1/R/2
1/R'= 2/R + 2/R
1/R'= 2+2/R
1/R' = 4/R
R' = R/4
Required Answer.
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