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2 ans =
Let the smaller number =x.
greater number =3x.
The new number after adding =3.
To the smaller number =x+3.
Equation: 3x-(x+3)=31.
3x-(x+3)=31.
3x+-x-3=31.
3x-x-3=31.
2x-3=31.
2x=31+3.
2x=34.
x=34/2
=17.
Smaller number (x) =17 .
Greater number (3x) =3x17.
=51 is the answer.
3 ans = Let the ones digit =x.
Sum of digit =14.
Tens digit =(14-x).
The original number =10(14-x)+x x 1.
=140-10+x.
140-9x.
New number after reversing the digit =10xx+(1x14-x).
10x+14-x.
9x+14.
Equation =9x+14+18=140-9x.
9x+14+18=140-9x.
9x+32=140-9x.
9x+9x=140-32.
19x=108.
x=108/8.
One's digit =6.
Ten's digit =14-x.
14-6.
8.
original number =86.
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