Question

Please anwer this. I need it fast

Answer 1

Answer:

(2,2)

THIS IS THE ANSWER

                           

Answer 2

Answer:

Coordinates are C(2,2)

Step-by-step explanation:

By using distance formula, we have:

AB = √[( x2 - x1)^2 + (y2 - y1)^2]

=> AB = √[( 2)^2 + (0)^2]

=> AB = √4

=> AB = 2 units

Now, All sides of a square are equal and let coordinates of C be C( x, y)

=> AB = BC

=> BC = 2 units

2 = √[( x - 2)^2 + ( y - 0)^2]

=> 2 = √[ x^2 + 4 - 4x + y^2]

CD = 2

=> 2 = √[( x - 0)^2 + ( y - 2)^2]

=> 2 = √[ x^2 + y^2 + 4 - 4y]

=> √[ x^2 + y^2 + 4 - 4y] = √[ x^2 + 4 - 4x + y^2]

=> x^2 + y^2 + 4 - 4y = x^2 + 4 - 4x + y^2

=> 4x = 4y

=> x = y. --------------------(1)

BD = √[ ( 2 - 0)^2 + ( 0-2)^2]

= √8 units

AC = BD. ( diagnols of a square are equal)

=> √8 = √[( x - 0)^2 + (y - 0)^2]

=> 8 = x ^2 + y^2

But from (1) , x = y

=> 8 = x^2 + x^2

=> x^2 = 4

=> x = 2 .

since x = y, y = 2

Therefore, coordinates of point C are C( 2,2)