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the distance between AB and CD = 2√3 cm & Difference between AB & CD =4 cm
Step-by-step explanation:
Let say DM ⊥ AB
=> Sin60 = DM/AD
=> √3 / 2 = DM/4
=> DM = 4√3 /2
=> DM = 2√3
the distance between AB and CD = 2√3
Cos 60 = AM/AD
=> 1/2 = AM/4
=> AM = 2
Similarly CN ⊥ AB
=> BN = 2
CD = AB - (AM + BN)
=> CD = 10 - (2 + 2)
=> CD = 6
Difference between AB & CD = 10 - 6 = 4 cm
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