Question

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Answer 1

Answer:

I hope this answer is right

Answer 2

It is given that :-

Present population (P) = 15625

Rate of increase (r) = 4% p.a.

Period (n) = 3 years

We know that :-

Population after 3 years

$= p( \frac{1 + r}{100})^{n}$

Substituting the values :-

$= 15625( \frac{1 + 4}{100})^{3}$

$= 15625 \times \frac{26}{25} \times \frac{26}{25} \times \frac{26}{25}$

$= 17576$

So the increase =

$17576 - 15625 = 1951$