Question

Please any answer this fast.........​

Answer 1

Heya

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Let the three no.s in A.P be

a , a + d and a + 2d

=>

ACCORDING TO THE QUESTION

a + a + d + a + 2d = 18

=>

3a + 3d = 18

=>

a + d = 6.... equation ( i )

d = 6 - a

a × ( a + 2d ) = 5d

=>

a² + 2ad - 5d = 0

a² + 2a ( 6 - a ) - 5( 6 -a )= 0

a² + 12a - 2a² -30 +5a = 0

=>

-a² + 12a +5a - 30 = 0

=>

a² - 17a + 30 = 0

=>

a² - 15a - 2a + 30 = 0

a ( a - 15 ) -2 ( a - 15 ) = 0

=>

a = 15 And a = 2

FOR a = 2

for a = 2 d = 4

So, the three no.s in A.P are

2 , 6 And 10